Special Array With X Elements Greater Than or Equal X
The problem is looking for a specific number x
that has a special property. This property is defined by the condition that there are exactly x
numbers in the nums
array that are greater than or equal to x
.
In other words, x
is the count of numbers in nums
which are greater than or equal to x
.
Let’s clarify it further with an example:
If we have nums = [3, 5]
, the output is 2
because there are 2
numbers (which are 3
and 5
) in nums
that are greater than or equal to 2
.
But if nums = [0,0]
, the output is 1
because there’s no x
that satisfies the condition. Here’s why:
 If
x = 0
, there should be0
numbers greater than or equal to0
, but there are2
.  If
x = 1
, there should be1
number greater than or equal to1
, but there are0
.  If
x = 2
, there should be2
numbers greater than or equal to2
, but there are0
.
So, we’re looking for a number x
that is equal to the count of numbers that are greater than or equal to x
in the nums
array. If there’s no such number, we return 1
.
The logic of the problem requires us to find a number x
such that exactly x
numbers in nums
are greater than or equal to x
. If no such number is found, then we should return 1
.


This code correctly handles the x = 0
case by ensuring that nums
should be an empty array in this case. For other values of x
, it counts the numbers in nums
that are greater than or equal to x
and checks if this count is equal to x
. If such an x
is found, it returns x
. If no such x
is found after checking all possible values, it returns 1
.
Beginner friendly version:


In this solution, the inner loop that counts the numbers greater than or equal to x
is explicitly written out, and the increment of count
is done as a separate step. This makes it easier to understand each step of the process.