Row With Maximum Ones
We need to go through each row in the matrix, count the number of ones, and keep track of the row that has the most ones. If two rows have the same number of ones, we prefer the row with a smaller index.
We can achieve this using a simple for loop to iterate through the rows of the matrix. In the loop, we use the builtin sum function to count the number of ones in each row (since ones are represented by the number 1 and zeros by the number 0, summing the row gives us the count of ones).
Python solution:


This solution works for all inputs within the problem’s constraints, and its time complexity is O(m*n), where m is the number of rows and n is the number of columns in the matrix.