Remove Digit From Number to Maximize Result


This code is doing the following:
 Creating an empty list,
arr
.  Looping through the indices of
number
. If the current digit is equal todigit
, it removes this digit fromnumber
and appends the resulting number toarr
.  Finding the maximum value in
arr
.  Converting this maximum value to a string and returning it.
Q&A
what is the mistake in my solution


Your solution seems to have a few errors and misunderstandings:
number=input()
anddigit=input()
: These lines are unnecessary. The function’s argumentsnumber
anddigit
are already being passed in when the function is called. You should remove these lines.if number[]==digit:
: This line has a syntax error. It seems like you want to iterate over the digits innumber
, but you forgot to include the index inside the brackets.arr.append(int(number[0::1]+number[_+1::]))
: This line will append the integer version of the stringnumber
without the current digit toarr
. However, your slicing seems to be off.number[0::1]
will include all the digits innumber
, andnumber[_+1::]
will include all digits after the current one. This would not exclude the current digit from the result.max(arr)
: This line returns the maximum value inarr
, but it does not convert it back to a string. Also, it’s not inside a return statement, so the function does not return anything.
A corrected version of your function could look like this:


This version of your function removes the digit
from number
at every possible position and stores the resulting numbers in arr
. Then it finds the maximum value in arr
, converts it to a string and returns it. However, this is not the correct approach to the problem because you’re not seeking to create the maximum number by removing a digit
at every possible position but to create the maximum number by removing a digit
once. For this reason, you need to follow a different approach like the one provided in the previous response.