HomeMinimum Seconds to Equalize a Circular Array1 2 3 4 5 6 7 8 class Solution: def minimumSeconds(self, nums: List[int]) -> int: pos, gap = {}, defaultdict(lambda: 0) for i, n in enumerate(nums + nums): if n in pos: gap[n] = max(gap[n], (i - pos[n]) // 2) pos[n] = i return min(gap.values())
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class Solution: def minimumSeconds(self, nums: List[int]) -> int: pos, gap = {}, defaultdict(lambda: 0) for i, n in enumerate(nums + nums): if n in pos: gap[n] = max(gap[n], (i - pos[n]) // 2) pos[n] = i return min(gap.values())