Generate a String With Characters That Have Odd Counts
The idea is to generate a string of ‘a’ characters of length n
if n
is odd, or a string of ‘a’ characters of length n  1
followed by a ‘b’ if n
is even. This ensures that every character in the string occurs an odd number of times, which is the problem’s requirement.
Python solution:


In this solution, we use the modulo operator to determine if n
is even or odd. If n
is odd, we return a string with ‘a’ repeated n
times. If n
is even, we return a string with ‘a’ repeated n  1
times, followed by a ‘b’. This ensures that each character in the string occurs an odd number of times.