Currency Arbitrage
Currency arbitrage involves exploiting differences in exchange rates to make a profit with a series of currency trades. Given exchange rates, we can find sequences that start and end with the same currency while gaining value.
Java example:
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| boolean findArbitrage(double[][] rates) {
int n = rates.length;
// Convert rates to graph
double[][] graph = new double[n][n];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
graph[i][j] = Math.log(rates[i][j]);
}
}
// Check for negative weight cycle
for (int k = 0; k < n; k++) {
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
graph[i][j] = Math.max(graph[i][j], graph[i][k] + graph[k][j]);
}
}
}
// Arbitrage exists if graph has negative cycle
for (int i = 0; i < n; i++) {
if (graph[i][i] < 0) return true;
}
return false;
}
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C++ example:
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| bool findArbitrage(vector<vector<double>>& rates) {
int n = rates.size();
// rates to graph
vector<vector<double>> graph(n, vector<double>(n));
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
graph[i][j] = log(rates[i][j]);
}
}
// Bellman-Ford
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
for (int k = 0; k < n; k++) {
graph[j][k] = max(graph[j][k], graph[j][i] + graph[i][k]);
}
}
}
// Check for negative cycle
for (int i = 0; i < n; i++) {
if (graph[i][i] < 0) return true;
}
return false;
}
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Python example:
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| import math
def find_arbitrage(rates):
n = len(rates)
graph = [[0] * n for _ in range(n)]
for i in range(n):
for j in range(n):
graph[i][j] = -math.log(rates[i][j])
# Bellman-Ford
for k in range(n):
for i in range(n):
for j in range(n):
graph[i][j] = max(graph[i][j], graph[i][k] + graph[k][j])
for i in range(n):
if graph[i][i] < 0:
return True
return False
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Currency arbitrage takes advantage of exchange rate mismatches for profit. Useful knowledge for finance and Forex markets.
Currency arbitrage is a financial strategy where you exploit differences in currency exchange rates to make a profit. Imagine you can trade between dollars, euros, and yen. If you can buy euros with dollars, then yen with euros, and finally convert yen back to more dollars than you started with, you’ve successfully performed currency arbitrage.
Code Examples
Java
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| public class CurrencyArbitrage {
public static void main(String[] args) {
double[][] rates = {{1, 0.5, 0.8}, {2, 1, 1.6}, {1.25, 0.625, 1}};
if (arbitrageExists(rates)) {
System.out.println("Arbitrage exists.");
} else {
System.out.println("No arbitrage opportunity.");
}
}
public static boolean arbitrageExists(double[][] rates) {
int n = rates.length;
for (int i = 0; i < n; i++) {
if (rates[i][i] > 1) {
return true;
}
}
return false;
}
}
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C++
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| #include <iostream>
using namespace std;
bool arbitrageExists(double rates[][3], int n) {
for (int i = 0; i < n; i++) {
if (rates[i][i] > 1) {
return true;
}
}
return false;
}
int main() {
double rates[3][3] = {{1, 0.5, 0.8}, {2, 1, 1.6}, {1.25, 0.625, 1}};
if (arbitrageExists(rates, 3)) {
cout << "Arbitrage exists.\n";
} else {
cout << "No arbitrage opportunity.\n";
}
}
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Python
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| def arbitrage_exists(rates):
n = len(rates)
for i in range(n):
if rates[i][i] > 1:
return True
return False
rates = [[1, 0.5, 0.8], [2, 1, 1.6], [1.25, 0.625, 1]]
if arbitrage_exists(rates):
print("Arbitrage exists.")
else:
print("No arbitrage opportunity.")
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In all these code snippets, we simply scan the diagonal elements of the rate matrix. If any of them are greater than 1, arbitrage exists. Note that this is a simplified example and real-world scenarios may require more complex logic.