Buy Two Chocolates

To solve this problem, we need to find the two smallest prices in the prices array. It is better to sort the prices array in ascending order, then pick the first two elements, which represent the minimum prices.

Here is the code:

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class Solution:
    def buyChoco(self, prices: List[int], money: int) -> int:
        # Sort prices in ascending order
        prices.sort()

        # Calculate the sum of the two smallest prices
        min_prices_sum = prices[0] + prices[1]

        # Check if the sum of the two smallest prices is less than or equal to the money
        if min_prices_sum <= money:
            # Return the leftover money after buying the two chocolates
            return money - min_prices_sum
        else:
            # Return the money as it is, as there is no way to buy two chocolates without ending up in debt
            return money

This function starts by sorting the prices list. Then it calculates the sum of the two smallest prices. If this sum is less than or equal to the money we have, we subtract the sum from the money to get the leftover amount and return it. If the sum of the two smallest prices is more than the money we have, we return the money as it is because we cannot buy two chocolates without going into debt.